# Mary, Tom, And Juan Have A Total Of 94 In Their Wallets. Tom

Mary, Tom, and Juan have a total of 94 in their wallets. Tom has 4 times what Juan has. Mary has \$6 less than Juan. How much does each have?

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Step-by-step

Step 1/1

Explanation:

Juan, Tom, Mary’s Wallets.

Let’s denote the amount of money Juan has as J, the amount Tom has as T, and the amount Mary has as M. From the problem, we have the following equations:

T M J = 94 (The total amount of money they have is 94) – (1)

T = 4J (Tom has 4 times what Juan has) – (2)

M = J – 6 (Mary has \$6 less than Juan) – (3)

We can substitute equations 2 and 3 into equation 1 to solve for J:

4J J – 6 J = 94

6J – 6 = 94

6J = 100

J = 100 / 6

J = 16.67

Substituting J = 16.67 into equations 2 and 3, we get:

T = 4 * 16.67 = 66.68

M = 16.67 – 6 = 10.67

So, Juan has approximately \$16.67, Tom has approximately \$66.68, and Mary has approximately \$10.67. Please note that it’s unusual to have cents in a wallet, so this problem might be about bank accounts or another form of money.

Summary: Juan has approximately \$16.67, Tom has around \$66.67 (four times Juan’s amount), and Mary has about \$10.67 ( \$6 less than Juan). Together, they have a total of \$94.